diff options
Diffstat (limited to 'Demo/comparisons/regextest.py')
| -rwxr-xr-x | Demo/comparisons/regextest.py | 46 |
1 files changed, 23 insertions, 23 deletions
diff --git a/Demo/comparisons/regextest.py b/Demo/comparisons/regextest.py index 97564b7939..e4e18d6d58 100755 --- a/Demo/comparisons/regextest.py +++ b/Demo/comparisons/regextest.py @@ -1,13 +1,13 @@ #! /usr/bin/env python # 1) Regular Expressions Test -# -# Read a file of (extended per egrep) regular expressions (one per line), +# +# Read a file of (extended per egrep) regular expressions (one per line), # and apply those to all files whose names are listed on the command line. # Basically, an 'egrep -f' simulator. Test it with 20 "vt100" patterns # against a five /etc/termcap files. Tests using more elaborate patters # would also be interesting. Your code should not break if given hundreds -# of regular expressions or binary files to scan. +# of regular expressions or binary files to scan. # This implementation: # - combines all patterns into a single one using ( ... | ... | ... ) @@ -24,27 +24,27 @@ from regex_syntax import * regex.set_syntax(RE_SYNTAX_EGREP) def main(): - pats = map(chomp, sys.stdin.readlines()) - bigpat = '(' + string.joinfields(pats, '|') + ')' - prog = regex.compile(bigpat) - - for file in sys.argv[1:]: - try: - fp = open(file, 'r') - except IOError, msg: - print "%s: %s" % (file, msg) - continue - lineno = 0 - while 1: - line = fp.readline() - if not line: - break - lineno = lineno + 1 - if prog.search(line) >= 0: - print "%s:%s:%s" % (file, lineno, line), + pats = map(chomp, sys.stdin.readlines()) + bigpat = '(' + string.joinfields(pats, '|') + ')' + prog = regex.compile(bigpat) + + for file in sys.argv[1:]: + try: + fp = open(file, 'r') + except IOError, msg: + print "%s: %s" % (file, msg) + continue + lineno = 0 + while 1: + line = fp.readline() + if not line: + break + lineno = lineno + 1 + if prog.search(line) >= 0: + print "%s:%s:%s" % (file, lineno, line), def chomp(s): - if s[-1:] == '\n': return s[:-1] - else: return s + if s[-1:] == '\n': return s[:-1] + else: return s main() |