Python 3: Replace iterator.next() with six.next(iterator)

2 files changed, 4 insertions, 2 deletions

diff --git a/paste/evalexception/middleware.py b/paste/evalexception/middleware.py
index cee9147..b6345c5 100644
--- a/paste/evalexception/middleware.py
+++ b/paste/evalexception/middleware.py
@@ -31,6 +31,7 @@ import sys
 import os
 import cgi
 import traceback
+import six
 from six.moves import cStringIO as StringIO
 import pprint
 import itertools
@@ -162,7 +163,7 @@ def get_debug_count(environ):
     if 'paste.evalexception.debug_count' in environ:
         return environ['paste.evalexception.debug_count']
     else:
-        environ['paste.evalexception.debug_count'] = next = debug_counter.next()
+        environ['paste.evalexception.debug_count'] = next = six.next(debug_counter)
         return next
 
 class EvalException(object):
diff --git a/paste/lint.py b/paste/lint.py
index 5505663..5eaec9a 100644
--- a/paste/lint.py
+++ b/paste/lint.py
@@ -110,6 +110,7 @@ Some of the things this checks:
 """
 
 import re
+import six
 import sys
 from types import DictType, StringType, TupleType, ListType
 import warnings
@@ -262,7 +263,7 @@ class IteratorWrapper(object):
     def next(self):
         assert not self.closed, (
             "Iterator read after closed")
-        v = self.iterator.next()
+        v = six.next(self.iterator)
         if self.check_start_response is not None:
             assert self.check_start_response, (
                 "The application returns and we started iterating over its body, but start_response has not yet been called")