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author | Jarrod Millman <millman@berkeley.edu> | 2008-09-02 20:32:38 +0000 |
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committer | Jarrod Millman <millman@berkeley.edu> | 2008-09-02 20:32:38 +0000 |
commit | d29107a248130bbb68ecac58d6720d716529141c (patch) | |
tree | 9e1408025c80d63fe9fa6151343a7b265ec3f654 /numpy/lib/scimath.py | |
parent | a4a7966cf7191c28a7054127fd3717d6c760d556 (diff) | |
download | numpy-d29107a248130bbb68ecac58d6720d716529141c.tar.gz |
reindenting prior to release
Diffstat (limited to 'numpy/lib/scimath.py')
-rw-r--r-- | numpy/lib/scimath.py | 6 |
1 files changed, 3 insertions, 3 deletions
diff --git a/numpy/lib/scimath.py b/numpy/lib/scimath.py index ed04d1ce5..0d765fa20 100644 --- a/numpy/lib/scimath.py +++ b/numpy/lib/scimath.py @@ -198,15 +198,15 @@ def sqrt(x): As the numpy.sqrt, this returns the principal square root of x, which is what most people mean when they use square root; the principal square root - of x is not any number z such as z^2 = x. + of x is not any number z such as z^2 = x. For positive numbers, the principal square root is defined as the positive - number z such as z^2 = x. + number z such as z^2 = x. The principal square root of -1 is i, the principal square root of any negative number -x is defined a i * sqrt(x). For any non zero complex number, it is defined by using the following branch cut: x = r e^(i t) with - r > 0 and -pi < t <= pi. The principal square root is then + r > 0 and -pi < t <= pi. The principal square root is then sqrt(r) e^(i t/2). """ x = _fix_real_lt_zero(x) |