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/* Get the frequency of the time base.
Copyright (C) 2012-2019 Free Software Foundation, Inc.
This file is part of the GNU C Library.
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, see
<http://www.gnu.org/licenses/>. */
#include <stdint.h>
#include <string.h>
#include <libc-internal.h>
#include <not-cancel.h>
#include <libc-vdso.h>
uint64_t
__get_timebase_freq (void)
{
hp_timing_t result = 0L;
#ifdef SHARED
/* The vDSO does not return an error (it clear cr0.so on returning). */
INTERNAL_SYSCALL_DECL (err);
result =
INTERNAL_VSYSCALL_NO_SYSCALL_FALLBACK (get_tbfreq, err, uint64_t, 0);
#else
/* We read the information from the /proc filesystem. /proc/cpuinfo
contains at least one line like:
timebase : 33333333
We search for this line and convert the number into an integer. */
int fd = __open_nocancel ("/proc/cpuinfo", O_RDONLY);
if (__glibc_unlikely (fd == -1))
return result;
/* The timebase will be in the 1st 1024 bytes for systems with up
to 8 processors. If the first read returns less then 1024
bytes read, we have the whole cpuinfo and can start the scan.
Otherwise we will have to read more to insure we have the
timebase value in the scan. */
char buf[1024];
ssize_t n;
n = __read_nocancel (fd, buf, sizeof (buf));
if (n == sizeof (buf))
{
/* We are here because the 1st read returned exactly sizeof
(buf) bytes. This implies that we are not at EOF and may
not have read the timebase value yet. So we need to read
more bytes until we know we have EOF. We copy the lower
half of buf to the upper half and read sizeof (buf)/2
bytes into the lower half of buf and repeat until we
reach EOF. We can assume that the timebase will be in
the last 512 bytes of cpuinfo, so two 512 byte half_bufs
will be sufficient to contain the timebase and will
handle the case where the timebase spans the half_buf
boundry. */
const ssize_t half_buf = sizeof (buf) / 2;
while (n >= half_buf)
{
memcpy (buf, buf + half_buf, half_buf);
n = __read_nocancel (fd, buf + half_buf, half_buf);
}
if (n >= 0)
n += half_buf;
}
__close_nocancel (fd);
if (__glibc_likely (n > 0))
{
char *mhz = memmem (buf, n, "timebase", 7);
if (__glibc_likely (mhz != NULL))
{
char *endp = buf + n;
/* Search for the beginning of the string. */
while (mhz < endp && (*mhz < '0' || *mhz > '9') && *mhz != '\n')
++mhz;
while (mhz < endp && *mhz != '\n')
{
if (*mhz >= '0' && *mhz <= '9')
{
result *= 10;
result += *mhz - '0';
}
++mhz;
}
}
}
#endif
return result;
}
weak_alias (__get_timebase_freq, __ppc_get_timebase_freq)
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