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BEGIN {
x = 5^4^3^2
print "# of digits =", length(x)
print substr(x, 1, 20), "...", substr(x, length(x) - 19, 20)
PREC = 1 + 3.321928095 * length(x); # 1 + digits * log2(10)
print "floating-point computation with precision =", PREC
y = 5.0^4.0^3.0^2.0
print "# of digits =", length(y)
print substr(y, 1, 20), "...", substr(y, length(y) - 19, 20)
}
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