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| author | Michael Niedermayer <michaelni@gmx.at> | 2009-03-30 10:39:20 +0000 |
|---|---|---|
| committer | Michael Niedermayer <michaelni@gmx.at> | 2009-03-30 10:39:20 +0000 |
| commit | 52760ed76e32af032f7640a9886631d889ad1511 (patch) | |
| tree | 786a5bbafaad2547a6cabfff05b3357b449a54f2 /doc/rate_distortion.txt | |
| parent | 767e14c3807b6e8d0a47459a1ffceb1665dad251 (diff) | |
| download | ffmpeg-52760ed76e32af032f7640a9886631d889ad1511.tar.gz | |
The definition of rate and distortion is not conditional of lambda being
fixed (at least the current text sounded odd to me).
Originally committed as revision 18244 to svn://svn.ffmpeg.org/ffmpeg/trunk
Diffstat (limited to 'doc/rate_distortion.txt')
| -rw-r--r-- | doc/rate_distortion.txt | 6 |
1 files changed, 4 insertions, 2 deletions
diff --git a/doc/rate_distortion.txt b/doc/rate_distortion.txt index 5f19b0d2ea..a7d2c878b2 100644 --- a/doc/rate_distortion.txt +++ b/doc/rate_distortion.txt @@ -21,8 +21,10 @@ Let's consider the problem of minimizing: distortion + lambda*rate -For a fixed lambda, rate would represent the filesize, while distortion is -the quality. Is this equivalent to finding the best quality for a given max +rate is the filesize +distortion is the quality +lambda is a fixed value choosen as a tradeoff between quality and filesize +Is this equivalent to finding the best quality for a given max filesize? The answer is yes. For each filesize limit there is some lambda factor for which minimizing above will get you the best quality (using your chosen quality measurement) at the desired (or lower) filesize. |