Make "ptype INTERNAL_FUNCTION" in Ada print like other languages

Currently, printing the type of an internal function in Ada shows
double <>s, like:

 (gdb) with language ada -- ptype $_isvoid
 type = <<internal function>>

while all other languages print it with a single <>, like:

 (gdb) with language c -- ptype $_isvoid
 type = <internal function>

I don't think there's a reason that Ada needs to be different.  We
currently print the double <>s because we take this path in
ada_print_type:

    switch (type->code ())
      {
      default:
	gdb_printf (stream, "<");
	c_print_type (type, "", stream, show, level, language_ada, flags);
	gdb_printf (stream, ">");
	break;

... and the type's name already has the <>s.

Fix this by simply adding an early check for
TYPE_CODE_INTERNAL_FUNCTION.

Approved-By: Andrew Burgess <aburgess@redhat.com>
Approved-By: Tom Tromey <tom@tromey.com>
Change-Id: Ic2b6527b9240a367471431023f6e27e6daed5501
Bug: https://sourceware.org/bugzilla/show_bug.cgi?id=30105

1 files changed, 7 insertions, 0 deletions

diff --git a/gdb/ada-typeprint.c b/gdb/ada-typeprint.c
index e95034c9285..3866b2d35eb 100644
--- a/gdb/ada-typeprint.c
+++ b/gdb/ada-typeprint.c
@@ -941,6 +941,13 @@ ada_print_type (struct type *type0, const char *varstring,
 		struct ui_file *stream, int show, int level,
 		const struct type_print_options *flags)
 {
+  if (type0->code () == TYPE_CODE_INTERNAL_FUNCTION)
+    {
+      c_print_type (type0, "", stream, show, level,
+		    language_ada, flags);
+      return;
+    }
+
   struct type *type = ada_check_typedef (ada_get_base_type (type0));
   /* If we can decode the original type name, use it.  However, there
      are cases where the original type is an internally-generated type