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authorDavid Feuer <david.feuer@gmail.com>2018-02-12 20:01:56 -0500
committerDavid Feuer <David.Feuer@gmail.com>2018-02-12 20:01:57 -0500
commitc9a88db3ac4f1c3e97e3492ebe076f2df6463540 (patch)
treeaf4cbdabd0f62b490c21b7a4bd38440221ba4dff /docs
parent583f561c285d1742b7e73128fd3331a49b87ec75 (diff)
downloadhaskell-c9a88db3ac4f1c3e97e3492ebe076f2df6463540.tar.gz
Make ($!) representation-polymorphic
Now that `($)` is representation-polymorphic, `($!)` should surely follow suit. Reviewers: hvr, bgamari, simonpj Reviewed By: bgamari, simonpj Subscribers: simonpj, rwbarton, thomie, carter Differential Revision: https://phabricator.haskell.org/D4382
Diffstat (limited to 'docs')
-rw-r--r--docs/users_guide/8.6.1-notes.rst2
1 files changed, 2 insertions, 0 deletions
diff --git a/docs/users_guide/8.6.1-notes.rst b/docs/users_guide/8.6.1-notes.rst
index c17664f1ae..e844ab6b2a 100644
--- a/docs/users_guide/8.6.1-notes.rst
+++ b/docs/users_guide/8.6.1-notes.rst
@@ -49,6 +49,8 @@ Template Haskell
``base`` library
~~~~~~~~~~~~~~~~
+``($!)`` is now representation-polymorphic like ``($)``.
+
Build system
~~~~~~~~~~~~