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author | David Feuer <david.feuer@gmail.com> | 2018-02-12 20:01:56 -0500 |
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committer | David Feuer <David.Feuer@gmail.com> | 2018-02-12 20:01:57 -0500 |
commit | c9a88db3ac4f1c3e97e3492ebe076f2df6463540 (patch) | |
tree | af4cbdabd0f62b490c21b7a4bd38440221ba4dff /docs | |
parent | 583f561c285d1742b7e73128fd3331a49b87ec75 (diff) | |
download | haskell-c9a88db3ac4f1c3e97e3492ebe076f2df6463540.tar.gz |
Make ($!) representation-polymorphic
Now that `($)` is representation-polymorphic, `($!)` should
surely follow suit.
Reviewers: hvr, bgamari, simonpj
Reviewed By: bgamari, simonpj
Subscribers: simonpj, rwbarton, thomie, carter
Differential Revision: https://phabricator.haskell.org/D4382
Diffstat (limited to 'docs')
-rw-r--r-- | docs/users_guide/8.6.1-notes.rst | 2 |
1 files changed, 2 insertions, 0 deletions
diff --git a/docs/users_guide/8.6.1-notes.rst b/docs/users_guide/8.6.1-notes.rst index c17664f1ae..e844ab6b2a 100644 --- a/docs/users_guide/8.6.1-notes.rst +++ b/docs/users_guide/8.6.1-notes.rst @@ -49,6 +49,8 @@ Template Haskell ``base`` library ~~~~~~~~~~~~~~~~ +``($!)`` is now representation-polymorphic like ``($)``. + Build system ~~~~~~~~~~~~ |