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+/* Copyright (C) 1991-2017 Free Software Foundation, Inc.
+ This file is part of the GNU C Library.
+
+ The GNU C Library is free software; you can redistribute it and/or
+ modify it under the terms of the GNU Lesser General Public
+ License as published by the Free Software Foundation; either
+ version 2.1 of the License, or (at your option) any later version.
+
+ The GNU C Library is distributed in the hope that it will be useful,
+ but WITHOUT ANY WARRANTY; without even the implied warranty of
+ MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
+ Lesser General Public License for more details.
+
+ You should have received a copy of the GNU Lesser General Public
+ License along with the GNU C Library; if not, see
+ <http://www.gnu.org/licenses/>. */
+
+/* Written by Paul Eggert <eggert@cs.ucla.edu>. */
+
+#include <time.h>
+
+#include <limits.h>
+#include <float.h>
+#include <stdint.h>
+
+#define TYPE_BITS(type) (sizeof (type) * CHAR_BIT)
+#define TYPE_FLOATING(type) ((type) 0.5 == 0.5)
+#define TYPE_SIGNED(type) ((type) -1 < 0)
+
+/* Return the difference between TIME1 and TIME0, where TIME0 <= TIME1.
+ time_t is known to be an integer type. */
+
+static double
+subtract (time_t time1, time_t time0)
+{
+ if (! TYPE_SIGNED (time_t))
+ return time1 - time0;
+ else
+ {
+ /* Optimize the common special cases where time_t
+ can be converted to uintmax_t without losing information. */
+ uintmax_t dt = (uintmax_t) time1 - (uintmax_t) time0;
+ double delta = dt;
+
+ if (UINTMAX_MAX / 2 < INTMAX_MAX)
+ {
+ /* This is a rare host where uintmax_t has padding bits, and possibly
+ information was lost when converting time_t to uintmax_t.
+ Check for overflow by comparing dt/2 to (time1/2 - time0/2).
+ Overflow occurred if they differ by more than a small slop.
+ Thanks to Clive D.W. Feather for detailed technical advice about
+ hosts with padding bits.
+
+ In the following code the "h" prefix means half. By range
+ analysis, we have:
+
+ -0.5 <= ht1 - 0.5*time1 <= 0.5
+ -0.5 <= ht0 - 0.5*time0 <= 0.5
+ -1.0 <= dht - 0.5*(time1 - time0) <= 1.0
+
+ If overflow has not occurred, we also have:
+
+ -0.5 <= hdt - 0.5*(time1 - time0) <= 0
+ -1.0 <= dht - hdt <= 1.5
+
+ and since dht - hdt is an integer, we also have:
+
+ -1 <= dht - hdt <= 1
+
+ or equivalently:
+
+ 0 <= dht - hdt + 1 <= 2
+
+ In the above analysis, all the operators have their exact
+ mathematical semantics, not C semantics. However, dht - hdt +
+ 1 is unsigned in C, so it need not be compared to zero. */
+
+ uintmax_t hdt = dt / 2;
+ time_t ht1 = time1 / 2;
+ time_t ht0 = time0 / 2;
+ time_t dht = ht1 - ht0;
+
+ if (2 < dht - hdt + 1)
+ {
+ /* Repair delta overflow.
+
+ The following expression contains a second rounding,
+ so the result may not be the closest to the true answer.
+ This problem occurs only with very large differences.
+ It's too painful to fix this portably. */
+
+ delta = dt + 2.0L * (UINTMAX_MAX - UINTMAX_MAX / 2);
+ }
+ }
+
+ return delta;
+ }
+}
+
+/* Return the difference between TIME1 and TIME0. */
+double
+__difftime (time_t time1, time_t time0)
+{
+ /* Convert to double and then subtract if no double-rounding error could
+ result. */
+
+ if (TYPE_BITS (time_t) <= DBL_MANT_DIG
+ || (TYPE_FLOATING (time_t) && sizeof (time_t) < sizeof (long double)))
+ return (double) time1 - (double) time0;
+
+ /* Likewise for long double. */
+
+ if (TYPE_BITS (time_t) <= LDBL_MANT_DIG || TYPE_FLOATING (time_t))
+ return (long double) time1 - (long double) time0;
+
+ /* Subtract the smaller integer from the larger, convert the difference to
+ double, and then negate if needed. */
+
+ return time1 < time0 ? - subtract (time0, time1) : subtract (time1, time0);
+}
+strong_alias (__difftime, difftime)