get_tree_entry(): do not call find_tree_entry() on an empty tree

We know we will find nothing.

This incidentally squelches false warning from gcc about potentially
uninitialized usage of t.entry fields. For an empty tree, it is true that
init_tree_desc() does not call decode_tree_entry() and the tree_desc is
left uninitialized, but find_tree_entry() only calls tree_entry_extract()
that uses the tree_desc while it has more things to read from the tree, so
the uninitialized t.entry fields are never used in such a case anyway.

Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 7 insertions, 3 deletions

diff --git a/tree-walk.c b/tree-walk.c
index f5d19f9cc1..cc2f14a0d6 100644
--- a/tree-walk.c
+++ b/tree-walk.c
@@ -465,7 +465,6 @@ int get_tree_entry(const unsigned char *tree_sha1, const char *name, unsigned ch
 	int retval;
 	void *tree;
 	unsigned long size;
-	struct tree_desc t;
 	unsigned char root[20];
 
 	tree = read_object_with_reference(tree_sha1, tree_type, &size, root);
@@ -478,8 +477,13 @@ int get_tree_entry(const unsigned char *tree_sha1, const char *name, unsigned ch
 		return 0;
 	}
 
-	init_tree_desc(&t, tree, size);
-	retval = find_tree_entry(&t, name, sha1, mode);
+	if (!size) {
+		retval = -1;
+	} else {
+		struct tree_desc t;
+		init_tree_desc(&t, tree, size);
+		retval = find_tree_entry(&t, name, sha1, mode);
+	}
 	free(tree);
 	return retval;
 }