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authorJunio C Hamano <gitster@pobox.com>2009-06-08 23:26:44 -0700
committerJunio C Hamano <gitster@pobox.com>2009-10-04 14:44:34 -0700
commit3af1cae469555485cd3ef003aa2a55bd2a4f544f (patch)
tree90d51c0e12927afc0fd6e71afec182f80babdc60 /t/t5515
parent57343652a55bdc3e7f3cf8c6def94dac482c72e5 (diff)
downloadgit-3af1cae469555485cd3ef003aa2a55bd2a4f544f.tar.gz
show-branch: fix segfault when showbranch.default exists
When running "git show-branch" without any parameter in a repository that has showbranch.default defined, we used to rely on the fact that our handcrafted option parsing loop never looked at av[0]. The array of default strings had the first real command line argument in default_arg[0], but the option parser wanted to look at the array starting at av[1], so we assigned the address of -1th element to av to force the loop start working from default_arg[0]. This no longer worked since 5734365 (show-branch: migrate to parse-options API, 2009-05-21), as parse_options_start() saved the incoming &av[0] in its ctx->out and later in parse_options_end() it did memmove to ctx->out (with ctx->cpidx == 0), overwriting the memory before default_arg[] array. I am not sure if this is a bug in parse_options(), or a bug in the caller, and tonight I do not have enough concentration to figure out which. In any case, this patch works the issue around. Signed-off-by: Junio C Hamano <gitster@pobox.com>
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