update_refs(): fix constness

The old signature of update_refs() required a
(const struct ref_update **) for its updates_orig argument.  The
"const" is presumably there to promise that the function will not
modify the contents of the structures.

But this declaration does not permit the function to be called with a
(struct ref_update **), which is perfectly legitimate.  C's type
system is not powerful enough to express what we'd like.  So remove
the first "const" from the declaration.

On the other hand, the function *can* promise not to modify the
pointers within the array that is passed to it without inconveniencing
its callers.  So add a "const" that has that effect, making the final
declaration
(struct ref_update * const *).

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 1 insertions, 1 deletions

diff --git a/refs.h b/refs.h
index a713b34ad8..08e60ac07f 100644
--- a/refs.h
+++ b/refs.h
@@ -228,7 +228,7 @@ int update_ref(const char *action, const char *refname,
 /**
  * Lock all refs and then perform all modifications.
  */
-int update_refs(const char *action, const struct ref_update **updates,
+int update_refs(const char *action, struct ref_update * const *updates,
 		int n, enum action_on_err onerr);
 
 extern int parse_hide_refs_config(const char *var, const char *value, const char *);