date: avoid "X years, 12 months" in relative dates

When relative dates are more than about a year ago, we start
writing them as "Y years, M months".  At the point where we
calculate Y and M, we have the time delta specified as a
number of days. We calculate these integers as:

  Y = days / 365
  M = (days % 365 + 15) / 30

This rounds days in the latter half of a month up to the
nearest month, so that day 16 is "1 month" (or day 381 is "1
year, 1 month").

We don't round the year at all, though, meaning we can end
up with "1 year, 12 months", which is silly; it should just
be "2 years".

Implement this differently with months of size

  onemonth = 365/12

so that

  totalmonths = (long)( (days + onemonth/2)/onemonth )
  years = totalmonths / 12
  months = totalmonths % 12

In order to do this without floats, we write the first formula as

  totalmonths = (days*12*2 + 365) / (365*2)

Tests and inspiration by Jeff King.

Helped-by: Jeff King <peff@peff.net>
Signed-off-by: Michael J Gruber <git@drmicha.warpmail.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>

1 files changed, 3 insertions, 2 deletions

diff --git a/date.c b/date.c
index 00f9eb5d0b..896fbb4806 100644
--- a/date.c
+++ b/date.c
@@ -129,8 +129,9 @@ const char *show_date_relative(unsigned long time, int tz,
 	}
 	/* Give years and months for 5 years or so */
 	if (diff < 1825) {
-		unsigned long years = diff / 365;
-		unsigned long months = (diff % 365 + 15) / 30;
+		unsigned long totalmonths = (diff * 12 * 2 + 365) / (365 * 2);
+		unsigned long years = totalmonths / 12;
+		unsigned long months = totalmonths % 12;
 		int n;
 		n = snprintf(timebuf, timebuf_size, "%lu year%s",
 				years, (years > 1 ? "s" : ""));