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! Program to test the MINLOC and MAXLOC intrinsics
program testmmloc
implicit none
integer, dimension (3, 3) :: a
integer, dimension (3) :: b
logical, dimension (3, 3) :: m, tr
integer i
character(len=10) line
a = reshape ((/1, 2, 3, 5, 4, 6, 9, 8, 7/), (/3, 3/));
tr = .true.
b = minloc (a, 1)
if (b(1) .ne. 1) STOP 1
if (b(2) .ne. 2) STOP 2
if (b(3) .ne. 3) STOP 3
b = -1
write (line, 9000) minloc(a,1)
read (line, 9000) b
if (b(1) .ne. 1) STOP 4
if (b(2) .ne. 2) STOP 5
if (b(3) .ne. 3) STOP 6
m = .true.
m(1, 1) = .false.
m(1, 2) = .false.
b = minloc (a, 1, m)
if (b(1) .ne. 2) STOP 7
if (b(2) .ne. 2) STOP 8
if (b(3) .ne. 3) STOP 9
b = minloc (a, 1, m .and. tr)
if (b(1) .ne. 2) STOP 10
if (b(2) .ne. 2) STOP 11
if (b(3) .ne. 3) STOP 12
b = -1
write (line, 9000) minloc(a, 1, m)
read (line, 9000) b
if (b(1) .ne. 2) STOP 13
if (b(2) .ne. 2) STOP 14
if (b(3) .ne. 3) STOP 15
b(1:2) = minloc(a)
if (b(1) .ne. 1) STOP 16
if (b(2) .ne. 1) STOP 17
b = -1
write (line, 9000) minloc(a)
read (line, 9000) b
if (b(1) .ne. 1) STOP 18
if (b(2) .ne. 1) STOP 19
if (b(3) .ne. 0) STOP 20
b(1:2) = minloc(a, mask=m)
if (b(1) .ne. 2) STOP 21
if (b(2) .ne. 1) STOP 22
b(1:2) = minloc(a, mask=m .and. tr)
if (b(1) .ne. 2) STOP 23
if (b(2) .ne. 1) STOP 24
b = -1
write (line, 9000) minloc(a, mask=m)
read (line, 9000) b
if (b(1) .ne. 2) STOP 25
if (b(2) .ne. 1) STOP 26
if (b(3) .ne. 0) STOP 27
b = maxloc (a, 1)
if (b(1) .ne. 3) STOP 28
if (b(2) .ne. 3) STOP 29
if (b(3) .ne. 1) STOP 30
b = -1
write (line, 9000) maxloc(a, 1)
read (line, 9000) b
if (b(1) .ne. 3) STOP 31
if (b(2) .ne. 3) STOP 32
if (b(3) .ne. 1) STOP 33
m = .true.
m(1, 2) = .false.
m(1, 3) = .false.
b = maxloc (a, 1, m)
if (b(1) .ne. 3) STOP 34
if (b(2) .ne. 3) STOP 35
if (b(3) .ne. 2) STOP 36
b = maxloc (a, 1, m .and. tr)
if (b(1) .ne. 3) STOP 37
if (b(2) .ne. 3) STOP 38
if (b(3) .ne. 2) STOP 39
b = -1
write (line, 9000) maxloc(a, 1, m)
read (line, 9000) b
if (b(1) .ne. 3) STOP 40
if (b(2) .ne. 3) STOP 41
if (b(3) .ne. 2) STOP 42
b(1:2) = maxloc(a)
if (b(1) .ne. 1) STOP 43
if (b(2) .ne. 3) STOP 44
b = -1
write (line, 9000) maxloc(a)
read (line, 9000) b
if (b(1) .ne. 1) STOP 45
if (b(2) .ne. 3) STOP 46
b(1:2) = maxloc(a, mask=m)
if (b(1) .ne. 2) STOP 47
if (b(2) .ne. 3) STOP 48
b(1:2) = maxloc(a, mask=m .and. tr)
if (b(1) .ne. 2) STOP 49
if (b(2) .ne. 3) STOP 50
b = -1
write (line, 9000) maxloc(a, mask=m)
read (line, 9000) b
if (b(1) .ne. 2) STOP 51
if (b(2) .ne. 3) STOP 52
if (b(3) .ne. 0) STOP 53
9000 format (3I3)
end program
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