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-rw-r--r--gcc/rtl.c84
1 files changed, 48 insertions, 36 deletions
diff --git a/gcc/rtl.c b/gcc/rtl.c
index 4b14dabf5cc..db28096ac65 100644
--- a/gcc/rtl.c
+++ b/gcc/rtl.c
@@ -24,7 +24,7 @@ Boston, MA 02111-1307, USA. */
#include "rtl.h"
#include "real.h"
#include "bitmap.h"
-
+#include "ggc.h"
#include "obstack.h"
#define obstack_chunk_alloc xmalloc
#define obstack_chunk_free free
@@ -244,18 +244,23 @@ rtvec_alloc (n)
int n;
{
rtvec rt;
- int i;
-
- rt = (rtvec) obstack_alloc (rtl_obstack,
- sizeof (struct rtvec_def)
- + (( n - 1) * sizeof (rtx)));
+
+ if (ggc_p)
+ rt = ggc_alloc_rtvec (n);
+ else
+ {
+ int i;
- /* clear out the vector */
- PUT_NUM_ELEM (rt, n);
+ rt = (rtvec) obstack_alloc (rtl_obstack,
+ sizeof (struct rtvec_def)
+ + (( n - 1) * sizeof (rtx)));
- for (i = 0; i < n; i++)
- rt->elem[i] = 0;
+ /* clear out the vector */
+ for (i = 0; i < n; i++)
+ rt->elem[i] = 0;
+ }
+ PUT_NUM_ELEM (rt, n);
return rt;
}
@@ -267,34 +272,40 @@ rtx_alloc (code)
RTX_CODE code;
{
rtx rt;
- register struct obstack *ob = rtl_obstack;
- register int nelts = GET_RTX_LENGTH (code);
- register int length = sizeof (struct rtx_def)
- + (nelts - 1) * sizeof (rtunion);
-
- /* This function is called more than any other in GCC,
- so we manipulate the obstack directly.
- Even though rtx objects are word aligned, we may be sharing an obstack
- with tree nodes, which may have to be double-word aligned. So align
- our length to the alignment mask in the obstack. */
-
- length = (length + ob->alignment_mask) & ~ ob->alignment_mask;
-
- if (ob->chunk_limit - ob->next_free < length)
- _obstack_newchunk (ob, length);
- rt = (rtx)ob->object_base;
- ob->next_free += length;
- ob->object_base = ob->next_free;
-
- /* We want to clear everything up to the FLD array. Normally, this is
- one int, but we don't want to assume that and it isn't very portable
- anyway; this is. */
-
- memset (rt, 0, sizeof (struct rtx_def) - sizeof (rtunion));
+ if (ggc_p)
+ rt = ggc_alloc_rtx (GET_RTX_LENGTH (code));
+ else
+ {
+ register struct obstack *ob = rtl_obstack;
+ register int nelts = GET_RTX_LENGTH (code);
+ register int length = sizeof (struct rtx_def)
+ + (nelts - 1) * sizeof (rtunion);
+
+ /* This function is called more than any other in GCC, so we
+ manipulate the obstack directly.
+
+ Even though rtx objects are word aligned, we may be sharing
+ an obstack with tree nodes, which may have to be double-word
+ aligned. So align our length to the alignment mask in the
+ obstack. */
+
+ length = (length + ob->alignment_mask) & ~ ob->alignment_mask;
+
+ if (ob->chunk_limit - ob->next_free < length)
+ _obstack_newchunk (ob, length);
+ rt = (rtx)ob->object_base;
+ ob->next_free += length;
+ ob->object_base = ob->next_free;
+
+ /* We want to clear everything up to the FLD array. Normally,
+ this is one int, but we don't want to assume that and it
+ isn't very portable anyway; this is. */
+
+ memset (rt, 0, sizeof (struct rtx_def) - sizeof (rtunion));
+ }
PUT_CODE (rt, code);
-
return rt;
}
@@ -304,7 +315,8 @@ void
rtx_free (x)
rtx x;
{
- obstack_free (rtl_obstack, x);
+ if (!ggc_p)
+ obstack_free (rtl_obstack, x);
}
/* Create a new copy of an rtx.