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authorforeese <foreese@138bc75d-0d04-0410-961f-82ee72b054a4>2016-11-10 21:54:48 +0000
committerforeese <foreese@138bc75d-0d04-0410-961f-82ee72b054a4>2016-11-10 21:54:48 +0000
commitac1739da2f62064ef7cd6ed8000a5bd64030b43e (patch)
tree1b848f307ec6f5df1c86adced8e648c82b497701 /gcc/fortran/interface.c
parent31db86df8fa1d3248c97de6c47dbd76fb74eaa8e (diff)
downloadgcc-ac1739da2f62064ef7cd6ed8000a5bd64030b43e.tar.gz
Fix some whitespace.
gcc/fortran/ * decl.c (get_struct_decl, gfc_match_map, gfc_match_union): Fix whitespace. * interface.c (gfc_compare_union_types): Likewise. git-svn-id: svn+ssh://gcc.gnu.org/svn/gcc/trunk@242057 138bc75d-0d04-0410-961f-82ee72b054a4
Diffstat (limited to 'gcc/fortran/interface.c')
-rw-r--r--gcc/fortran/interface.c64
1 files changed, 32 insertions, 32 deletions
diff --git a/gcc/fortran/interface.c b/gcc/fortran/interface.c
index 98a61dfe3bc..a0cb0bb9ce3 100644
--- a/gcc/fortran/interface.c
+++ b/gcc/fortran/interface.c
@@ -558,46 +558,46 @@ gfc_compare_union_types (gfc_symbol *un1, gfc_symbol *un2)
we will say they are not equal for the purposes of this test; therefore
we compare the maps sequentially. */
for (;;)
- {
- map1_t = map1->ts.u.derived;
- map2_t = map2->ts.u.derived;
+ {
+ map1_t = map1->ts.u.derived;
+ map2_t = map2->ts.u.derived;
- cmp1 = map1_t->components;
- cmp2 = map2_t->components;
+ cmp1 = map1_t->components;
+ cmp2 = map2_t->components;
- /* Protect against null components. */
- if (map1_t->attr.zero_comp != map2_t->attr.zero_comp)
- return 0;
+ /* Protect against null components. */
+ if (map1_t->attr.zero_comp != map2_t->attr.zero_comp)
+ return 0;
- if (map1_t->attr.zero_comp)
- return 1;
+ if (map1_t->attr.zero_comp)
+ return 1;
- for (;;)
- {
- /* No two fields will ever point to the same map type unless they are
- the same component, because one map field is created with its type
- declaration. Therefore don't worry about recursion here. */
- /* TODO: worry about recursion into parent types of the unions? */
- if (compare_components (cmp1, cmp2, map1_t, map2_t) == 0)
- return 0;
+ for (;;)
+ {
+ /* No two fields will ever point to the same map type unless they are
+ the same component, because one map field is created with its type
+ declaration. Therefore don't worry about recursion here. */
+ /* TODO: worry about recursion into parent types of the unions? */
+ if (compare_components (cmp1, cmp2, map1_t, map2_t) == 0)
+ return 0;
- cmp1 = cmp1->next;
- cmp2 = cmp2->next;
+ cmp1 = cmp1->next;
+ cmp2 = cmp2->next;
- if (cmp1 == NULL && cmp2 == NULL)
- break;
- if (cmp1 == NULL || cmp2 == NULL)
- return 0;
- }
+ if (cmp1 == NULL && cmp2 == NULL)
+ break;
+ if (cmp1 == NULL || cmp2 == NULL)
+ return 0;
+ }
- map1 = map1->next;
- map2 = map2->next;
+ map1 = map1->next;
+ map2 = map2->next;
- if (map1 == NULL && map2 == NULL)
- break;
- if (map1 == NULL || map2 == NULL)
- return 0;
- }
+ if (map1 == NULL && map2 == NULL)
+ break;
+ if (map1 == NULL || map2 == NULL)
+ return 0;
+ }
return 1;
}