/* Copyright (c) 2000 TXT DataKonsult Ab & Monty Program Ab Copyright (c) 2009-2011, Monty Program Ab Redistribution and use in source and binary forms, with or without modification, are permitted provided that the following conditions are met: 1. Redistributions of source code must retain the above copyright notice, this list of conditions and the following disclaimer. 2. Redistributions in binary form must the following disclaimer in the documentation and/or other materials provided with the distribution. THIS SOFTWARE IS PROVIDED BY ``AS IS'' AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE. */ /* str2int(src, radix, lower, upper, &val) converts the string pointed to by src to an integer and stores it in val. It skips leading spaces and tabs (but not newlines, formfeeds, backspaces), then it accepts an optional sign and a sequence of digits in the specified radix. The result should satisfy lower <= *val <= upper. The result is a pointer to the first character after the number; trailing spaces will NOT be skipped. If an error is detected, the result will be NullS, the value put in val will be 0, and errno will be set to EDOM if there are no digits ERANGE if the result would overflow or otherwise fail to lie within the specified bounds. Check that the bounds are right for your machine. This looks amazingly complicated for what you probably thought was an easy task. Coping with integer overflow and the asymmetric range of twos complement machines is anything but easy. So that users of atoi and atol can check whether an error occurred, I have taken a wholly unprecedented step: errno is CLEARED if this call has no problems. */ #include "strings_def.h" #include #include "my_sys.h" /* defines errno */ #include #define char_val(X) (X >= '0' && X <= '9' ? X-'0' :\ X >= 'A' && X <= 'Z' ? X-'A'+10 :\ X >= 'a' && X <= 'z' ? X-'a'+10 :\ '\177') char *str2int(register const char *src, register int radix, long int lower, long int upper, long int *val) { int sign; /* is number negative (+1) or positive (-1) */ int n; /* number of digits yet to be converted */ long limit; /* "largest" possible valid input */ long scale; /* the amount to multiply next digit by */ long sofar; /* the running value */ register int d; /* (negative of) next digit */ char *start; int digits[32]; /* Room for numbers */ /* Make sure *val is sensible in case of error */ *val = 0; /* Check that the radix is in the range 2..36 */ #ifndef DBUG_OFF if (radix < 2 || radix > 36) { errno=EDOM; return NullS; } #endif /* The basic problem is: how do we handle the conversion of a number without resorting to machine-specific code to check for overflow? Obviously, we have to ensure that no calculation can overflow. We are guaranteed that the "lower" and "upper" arguments are valid machine integers. On sign-and-magnitude, twos-complement, and ones-complement machines all, if +|n| is representable, so is -|n|, but on twos complement machines the converse is not true. So the "maximum" representable number has a negative representative. Limit is set to MY_MIN(-|lower|,-|upper|); this is the "largest" number we are concerned with. */ /* Calculate Limit using Scale as a scratch variable */ if ((limit = lower) > 0) limit = -limit; if ((scale = upper) > 0) scale = -scale; if (scale < limit) limit = scale; /* Skip leading spaces and check for a sign. Note: because on a 2s complement machine MinLong is a valid integer but |MinLong| is not, we have to keep the current converted value (and the scale!) as *negative* numbers, so the sign is the opposite of what you might expect. */ while (my_isspace(&my_charset_latin1,*src)) src++; sign = -1; if (*src == '+') src++; else if (*src == '-') src++, sign = 1; /* Skip leading zeros so that we never compute a power of radix in scale that we won't have a need for. Otherwise sticking enough 0s in front of a number could cause the multiplication to overflow when it neededn't. */ start=(char*) src; while (*src == '0') src++; /* Move over the remaining digits. We have to convert from left to left in order to avoid overflow. Answer is after last digit. */ for (n = 0; (digits[n]=char_val(*src)) < radix && n < 20; n++,src++) ; /* Check that there is at least one digit */ if (start == src) { errno=EDOM; return NullS; } /* The invariant we want to maintain is that src is just to the right of n digits, we've converted k digits to sofar, scale = -radix**k, and scale < sofar < 0. Now if the final number is to be within the original Limit, we must have (to the left)*scale+sofar >= Limit, or (to the left)*scale >= Limit-sofar, i.e. the digits to the left of src must form an integer <= (Limit-sofar)/(scale). In particular, this is true of the next digit. In our incremental calculation of Limit, IT IS VITAL that (-|N|)/(-|D|) = |N|/|D| */ for (sofar = 0, scale = -1; --n >= 1;) { if ((long) -(d=digits[n]) < limit) { errno=ERANGE; return NullS; } limit = (limit+d)/radix, sofar += d*scale; scale *= radix; } if (n == 0) { if ((long) -(d=digits[n]) < limit) /* get last digit */ { errno=ERANGE; return NullS; } sofar+=d*scale; } /* Now it might still happen that sofar = -32768 or its equivalent, so we can't just multiply by the sign and check that the result is in the range lower..upper. All of this caution is a right pain in the neck. If only there were a standard routine which says generate thus and such a signal on integer overflow... But not enough machines can do it *SIGH*. */ if (sign < 0) { if (sofar < -LONG_MAX || (sofar= -sofar) > upper) { errno=ERANGE; return NullS; } } else if (sofar < lower) { errno=ERANGE; return NullS; } *val = sofar; errno=0; /* indicate that all went well */ return (char*) src; } /* These are so slow compared with ordinary, optimized atoi */ #ifdef WANT_OUR_ATOI int atoi(const char *src) { long val; str2int(src, 10, (long) INT_MIN, (long) INT_MAX, &val); return (int) val; } long atol(const char *src) { long val; str2int(src, 10, LONG_MIN, LONG_MAX, &val); return val; } #endif /* WANT_OUR_ATOI */