//===----------------------------------------------------------------------===// // // Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions. // See https://llvm.org/LICENSE.txt for license information. // SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception // //===----------------------------------------------------------------------===// // // UNSUPPORTED: no-threads // // class condition_variable; // void notify_one(); // NOTE: `notify_one` is just a wrapper around pthread_cond_signal, but // POSIX does not guarantee that one and only one thread will be woken: // // https://pubs.opengroup.org/onlinepubs/9699919799/functions/pthread_cond_signal.html // // Quote: // Multiple Awakenings by Condition Signal // On a multi-processor, it may be impossible for an implementation of // pthread_cond_signal() to avoid the unblocking of more than one thread // blocked on a condition variable. For example... // NOTE: In previous versions of this test, `notify_one` was called WITHOUT // holding the lock but POSIX says (in the aforementioned URL) that: // ...if predictable scheduling behavior is required, then that mutex shall // be locked by the thread calling pthread_cond_broadcast() or // pthread_cond_signal(). #include #include #include #include #include #include "make_test_thread.h" #include "test_macros.h" std::condition_variable cv; std::mutex mut; std::atomic_int test1(0); std::atomic_int test2(0); std::atomic_int ready(2); std::atomic_int which(0); void f1() { std::unique_lock lk(mut); assert(test1 == 0); --ready; while (test1 == 0) cv.wait(lk); which = 1; assert(test1 == 1); test1 = 2; } void f2() { std::unique_lock lk(mut); assert(test2 == 0); --ready; while (test2 == 0) cv.wait(lk); which = 2; assert(test2 == 1); test2 = 2; } int main(int, char**) { std::thread t1 = support::make_test_thread(f1); std::thread t2 = support::make_test_thread(f2); { while (ready > 0) std::this_thread::yield(); // At this point: // 1) Both f1 and f2 have entered their condition variable wait. // 2) Either f1 or f2 has the mutex locked and is about to wait. std::unique_lock lk(mut); test1 = 1; test2 = 1; ready = 1; cv.notify_one(); } { while (which == 0) std::this_thread::yield(); std::unique_lock lk(mut); if (test1 == 2) { assert(test2 == 1); t1.join(); test1 = 0; } else { assert(test1 == 1); assert(test2 == 2); t2.join(); test2 = 0; } which = 0; cv.notify_one(); } { while (which == 0) std::this_thread::yield(); std::unique_lock lk(mut); if (test1 == 2) { assert(test2 == 0); t1.join(); test1 = 0; } else { assert(test1 == 0); assert(test2 == 2); t2.join(); test2 = 0; } } return 0; }