From 898ff03e1e7925ecde3da66327d3cdc7e07625ba Mon Sep 17 00:00:00 2001
From: Serhiy Storchaka <storchaka@gmail.com>
Date: Fri, 5 May 2017 08:53:40 +0300
Subject: bpo-30215: Make re.compile() locale agnostic. (#1361)

Compiled regular expression objects with the re.LOCALE flag no longer
depend on the locale at compile time.  Only the locale at matching
time affects the result of matching.
---
 Lib/re.py | 12 ++----------
 1 file changed, 2 insertions(+), 10 deletions(-)

(limited to 'Lib/re.py')

diff --git a/Lib/re.py b/Lib/re.py
index 7053eddbe0..d0ee5db175 100644
--- a/Lib/re.py
+++ b/Lib/re.py
@@ -268,9 +268,7 @@ _MAXCACHE = 512
 def _compile(pattern, flags):
     # internal: compile pattern
     try:
-        p, loc = _cache[type(pattern), pattern, flags]
-        if loc is None or loc == _locale.setlocale(_locale.LC_CTYPE):
-            return p
+        return _cache[type(pattern), pattern, flags]
     except KeyError:
         pass
     if isinstance(pattern, _pattern_type):
@@ -284,13 +282,7 @@ def _compile(pattern, flags):
     if not (flags & DEBUG):
         if len(_cache) >= _MAXCACHE:
             _cache.clear()
-        if p.flags & LOCALE:
-            if not _locale:
-                return p
-            loc = _locale.setlocale(_locale.LC_CTYPE)
-        else:
-            loc = None
-        _cache[type(pattern), pattern, flags] = p, loc
+        _cache[type(pattern), pattern, flags] = p
     return p
 
 @functools.lru_cache(_MAXCACHE)
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