/* Output Graphviz specification of a state machine generated by Bison. Copyright (C) 2006-2007, 2009-2015, 2018-2022 Free Software Foundation, Inc. This file is part of Bison, the GNU Compiler Compiler. This program is free software: you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program. If not, see . */ /* Written by Paul Eggert and Satya Kiran Popuri. */ #include #include "system.h" #include #include "files.h" #include "gram.h" #include "graphviz.h" #include "tables.h" /* Return an unambiguous printable representation for NAME, suitable for C strings. Use slot 2 since the user may use slots 0 and 1. */ static char * quote (char const *name) { return quotearg_n_style (2, c_quoting_style, name); } void start_graph (FILE *fout) { fprintf (fout, _("// Generated by %s.\n" "// Report bugs to <%s>.\n" "// Home page: <%s>.\n" "\n"), PACKAGE_STRING, PACKAGE_BUGREPORT, PACKAGE_URL); fprintf (fout, "digraph %s\n" "{\n", quote (grammar_file)); fprintf (fout, " node [fontname = courier, shape = box, colorscheme = paired6]\n" " edge [fontname = courier]\n" "\n"); } void output_node (int id, char const *label, FILE *fout) { fprintf (fout, " %d [label=\"%s\"]\n", id, label); } void output_edge (int source, int destination, char const *label, char const *style, FILE *fout) { fprintf (fout, " %d -> %d [style=%s", source, destination, style); if (label) { fputs (" label=\"", fout); for (const char *cp = label; *cp; ++cp) switch (*cp) { case '"': fputs ("\\\"", fout); break; case '\\': fputs ("\\\\", fout); break; default: fputc (*cp, fout); break; } fputc ('"', fout); } fputs ("]\n", fout); } static void no_reduce_bitset_init (state const *s, bitset *no_reduce_set) { *no_reduce_set = bitset_create (ntokens, BITSET_FIXED); bitset_zero (*no_reduce_set); { int n; FOR_EACH_SHIFT (s->transitions, n) bitset_set (*no_reduce_set, TRANSITION_SYMBOL (s->transitions, n)); } for (int n = 0; n < s->errs->num; ++n) if (s->errs->symbols[n]) bitset_set (*no_reduce_set, s->errs->symbols[n]->content->number); } /* Show the reductions from state SOURCE on rule RULENO. */ static void conclude_red (struct obstack *out, int source, rule_number ruleno, bool enabled, bool first, FILE *fout) { /* If no lookahead tokens were valid transitions, this reduction is actually hidden, so cancel everything. */ if (first) (void) obstack_finish0 (out); else { char const *ed = enabled ? "" : "d"; /* First, build the edge's head. The name of reduction nodes is "nRm", with n the source state and m the rule number. This is because we don't want all the reductions bearing a same rule number to point to the same state, since that is not the desired format. */ fprintf (fout, " %d -> \"%dR%d%s\" [", source, source, ruleno, ed); /* (The lookahead tokens have been added to the beginning of the obstack, in the caller function.) */ if (! obstack_empty_p (out)) { char *label = obstack_finish0 (out); fprintf (fout, "label=\"[%s]\", ", label); obstack_free (out, label); } /* Then, the edge's tail. */ fprintf (fout, "style=solid]\n"); /* Build the associated diamond representation of the target rule. */ fprintf (fout, " \"%dR%d%s\" [label=\"", source, ruleno, ed); bool const final = rule_is_initial (&rules[ruleno]); if (final) fprintf (fout, "Acc"); else fprintf (fout, "R%d", ruleno); char const *color = !enabled ? "5" : final ? "1" : "3"; fprintf (fout, "\", fillcolor=%s, shape=diamond, style=filled]\n", color); } } static bool print_token (struct obstack *out, bool first, char const *tok) { if (! first) obstack_sgrow (out, ", "); obstack_backslash (out, tok); return false; } void output_red (state const *s, reductions const *reds, FILE *fout) { bitset no_reduce_set; no_reduce_bitset_init (s, &no_reduce_set); rule *default_reduction = yydefact[s->number] ? &rules[yydefact[s->number] - 1] : NULL; /* Two obstacks are needed: one for the enabled reductions, and one for the disabled reductions, because in the end we want two separate edges, even though in most cases only one will actually be printed. */ struct obstack dout; struct obstack eout; obstack_init (&dout); obstack_init (&eout); const int source = s->number; for (int j = 0; j < reds->num; ++j) { bool defaulted = default_reduction && default_reduction == reds->rules[j]; /* Build the lookahead tokens lists, one for enabled transitions and one for disabled transitions. */ bool firstd = true; bool firste = true; rule_number ruleno = reds->rules[j]->number; if (reds->lookaheads) for (int i = 0; i < ntokens; i++) if (bitset_test (reds->lookaheads[j], i)) { if (bitset_test (no_reduce_set, i)) firstd = print_token (&dout, firstd, symbols[i]->tag); else { if (! defaulted) firste = print_token (&eout, firste, symbols[i]->tag); bitset_set (no_reduce_set, i); } } /* Do the actual output. */ conclude_red (&dout, source, ruleno, false, firstd, fout); conclude_red (&eout, source, ruleno, true, firste && !defaulted, fout); } obstack_free (&dout, 0); obstack_free (&eout, 0); bitset_free (no_reduce_set); } void finish_graph (FILE *fout) { fputs ("}\n", fout); }