/* This testcase is part of GDB, the GNU debugger. Copyright 2010-2022 Free Software Foundation, Inc. This program is free software; you can redistribute it and/or modify it under the terms of the GNU General Public License as published by the Free Software Foundation; either version 3 of the License, or (at your option) any later version. This program is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details. You should have received a copy of the GNU General Public License along with this program. If not, see . */ /* This program tests tracepoint speed. It consists of two identical loops, which in normal execution will run for exactly the same amount of time. A tracepoint in the second loop will slow it down by some amount, and then the program will report the slowdown observed. */ /* While primarily designed for the testsuite, it can also be used for interactive testing. */ #include #include #include #include #include int trace_speed_test (void); /* We mark these globals as volatile so the speed-measuring loops don't get totally emptied out at high optimization levels. */ volatile int globfoo, globfoo2, globfoo3; volatile short globarr[80000]; int init_iters = 10 * 1000; int iters; int max_iters = 1000 * 1000 * 1000; int numtps = 1; unsigned long long now2, now3, now4, now5; int total1, total2, idelta, mindelta, nsdelta; int nspertp = 0; /* Return CPU usage (both user and system - trap-based tracepoints use a bunch of system time). */ unsigned long long myclock () { struct timeval tm; gettimeofday (&tm, NULL); return (((unsigned long long) tm.tv_sec) * 1000000) + tm.tv_usec; } int main(int argc, char **argv) { int problem; iters = init_iters; while (1) { numtps = 1; /* set pre-run breakpoint here */ /* Keep trying the speed test, with more iterations, until we get to a reasonable number. */ while ((problem = trace_speed_test())) { /* If iteration isn't working, give up. */ if (iters > max_iters) { printf ("Gone over %d iterations, giving up\n", max_iters); break; } if (problem < 0) { printf ("Negative times, giving up\n"); break; } iters *= 2; printf ("Doubled iterations to %d\n", iters); } printf ("Tracepoint time is %d ns\n", nspertp); /* This is for the benefit of interactive testing and attaching, keeps the program from pegging the machine. */ sleep (1); /* set post-run breakpoint here */ /* Issue a little bit of output periodically, so we can see if program is alive or hung. */ printf ("%s keeping busy, clock=%llu\n", argv[0], myclock ()); } return 0; } int trace_speed_test (void) { int i; /* Overall loop run time deltas under 1 ms are likely noise and should be ignored. */ mindelta = 1000; // The bodies of the two loops following must be identical. now2 = myclock (); globfoo2 = 1; for (i = 0; i < iters; ++i) { globfoo2 *= 45; globfoo2 += globfoo + globfoo3; globfoo2 *= globfoo + globfoo3; globfoo2 -= globarr[4] + globfoo3; globfoo2 *= globfoo + globfoo3; globfoo2 += globfoo + globfoo3; } now3 = myclock (); total1 = now3 - now2; now4 = myclock (); globfoo2 = 1; for (i = 0; i < iters; ++i) { globfoo2 *= 45; globfoo2 += globfoo + globfoo3; /* set tracepoint here */ globfoo2 *= globfoo + globfoo3; globfoo2 -= globarr[4] + globfoo3; globfoo2 *= globfoo + globfoo3; globfoo2 += globfoo + globfoo3; } now5 = myclock (); total2 = now5 - now4; /* Report on the test results. */ nspertp = 0; idelta = total2 - total1; printf ("Loops took %d usec and %d usec, delta is %d usec, %d iterations\n", total1, total2, idelta, iters); /* If the second loop seems to run faster, things are weird so give up. */ if (idelta < 0) return -1; if (idelta > mindelta /* Total test time should be between 15 and 30 seconds. */ && (total1 + total2) > (15 * 1000000) && (total1 + total2) < (30 * 1000000)) { nsdelta = (((unsigned long long) idelta) * 1000) / iters; printf ("Second loop took %d ns longer per iter than first\n", nsdelta); nspertp = nsdelta / numtps; printf ("%d ns per tracepoint\n", nspertp); printf ("Base iteration time %d ns\n", ((int) (((unsigned long long) total1) * 1000) / iters)); printf ("Total test time %d secs\n", ((int) ((now5 - now2) / 1000000))); /* Speed test ran with no problem. */ return 0; } /* The test run was too brief, or otherwise not useful. */ return 1; }